Notice that we are given the mass of both reactants: this way we require to identify thelimiting reactant, i beg your pardon is the reactant that forms the less amount that product.
You are watching: Nahco3 hcl balanced equation
This is due to the fact that once the limiting reactant is all used up, the reaction have the right to no much longer proceed and make much more products.
This way the limiting reactant determines themaximum massive of the product (CO2) formed.
We need to perform amole-to-mole comparisonbetween every reactant and CO2.
Balanced Reaction:NaHCO3(s) + HCl(aq)→NaCl(aq) + H2O(l) + CO2(g)
For NaHCO3:From the balanced equation,1 mole that NaHCO3 form 1 mole of CO2.
Themoles of CO2formed by8.67 gNaHCO3is:
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Sodium bicarbonate reacts through hydrochloric mountain in a gas-forming reaction to create aqueous sodium chloride, water, and also carbon dioxide gas:
NaHCO3(s) + HCl(aq)→NaCl(aq) + H2O(l) + CO2(g)
Determine the fixed of CO2 gas developed when 8.67 g of NaHCO3 is added to a equipment that consists of 5.65 g of HCl.
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