Notice that we are given the mass of both reactants: this way we require to identify thelimiting reactant, i beg your pardon is the reactant that forms the less amount that product.

You are watching: Nahco3 hcl balanced equation

This is due to the fact that once the limiting reactant is all used up, the reaction have the right to no much longer proceed and make much more products.

This way the limiting reactant determines themaximum massive of the product (CO2) formed.

We need to perform amole-to-mole comparisonbetween every reactant and CO2.

Balanced Reaction:NaHCO3(s) + HCl(aq)→NaCl(aq) + H2O(l) + CO2(g)

For NaHCO3:From the balanced equation,1 mole that NaHCO3 form 1 mole of CO2.

Themoles of CO2formed by8.67 gNaHCO3is:


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Problem Details

Sodium bicarbonate reacts through hydrochloric mountain in a gas-forming reaction to create aqueous sodium chloride, water, and also carbon dioxide gas:

NaHCO3(s) + HCl(aq)→NaCl(aq) + H2O(l) + CO2(g)

Determine the fixed of CO2 gas developed when 8.67 g of NaHCO3 is added to a equipment that consists of 5.65 g of HCl.


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Frequently inquiry Questions


What scientific concept do you need to understand in order to solve this problem?

Our tutors have indicated the to deal with this problem you will require to use the Limiting Reagent concept. You deserve to view video clip lessons to find out Limiting Reagent. Or if girlfriend need much more Limiting Reagent practice, you can additionally practice Limiting Reagent exercise problems.


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Based on our data, we think this difficulty is pertinent for Professor Blankenship's class at UGA.


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