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Re: If 2^x - 2^(x - 2) = 3*2^13 what is the value of x?<#permalink>
14 Jun 2018, 07:07
Hey ! Unfortunately, i still don"t gain where the "3" come from... Simply don"t check out it... Might anyone explain further in an ext detail?! would be great!
Step by step:(2^x-2^x-2=3*2^13) ~ this (2^x-2^x*2^-2=3*2^13) just how do we added 2 on the left next ? (2^x-frac2^x2^2=3*2^13) how do we get fraction on the left next ? and how after ~ this (2^x(1-frac12^2)=3*2^13) we obtain this top top the left next (2^x(frac2^2-12^2)=3*2^13)(2^x*frac32^2=3*2^13)(2^x=2^15)(x=15).Hope it"s clear.
Hi pushpitkc, can you please describe some steps listed below ? (2^x-2^x*2^-2=3*2^13) just how do we extr 2 on the left side ? (2^x-frac2^x2^2=3*2^13) exactly how do us get portion on the left next ? (2^x(1-frac12^2)=3*2^13) just how after this (2^x(frac2^2-12^2)=3*2^13) we gain this on the left side (2^x*frac32^2=3*2^13) and how we gain this ~ above the left next ? (2^x=2^15) hope this action will be clean after the ahead one (x=15).many many thanks
Hi pushpitkc, can you please explain some steps below ? (2^x-2^x*2^-2=3*2^13) how do we additional 2 ~ above the left side ? (2^x-frac2^x2^2=3*2^13) exactly how do we get fraction on the left side ? (2^x(1-frac12^2)=3*2^13) just how after this (2^x(frac2^2-12^2)=3*2^13) we obtain this on the left next (2^x*frac32^2=3*2^13) and how we acquire this on the left next ? (2^x=2^15) hopefully this step will be clear after the vault one (x=15).many thanks
Hi dave13Some formulae in exponents that you should remember in exponents(a^0 = 1) | (a^1 = a) | (sqrta = a^frac12) | (a^-n = frac1a^n)(a^m+n = a^m*a^n) | (fraca^ma^n=a^m−n) | (a^n = frac1a^-n)Coming earlier to the trouble at hand(2^x-2^x*2^-2=3*2^13) (2^x-frac2^x2^2=3*2^13) Here, (2^x-2 = 2^x + (-2) = 2^x*2^-2) (2^x(1-frac12^2)=3*2^13) Here, us take (2^x) as typical from both the expressions(2^x(frac2^2-12^2)=3*2^13) Here, we simplify (1 - frac12^2) as (frac2^2 - 12^2 = frac4-12^2 = frac32^2)(2^x*frac32^2=3*2^13) -> (2^x=2^15) Here, we take (2^2) indigenous left hand side to appropriate hand side_________________
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Hi pushpitkc, deserve to you please explain some steps below ? (2^x-2^x*2^-2=3*2^13) exactly how do we added 2 ~ above the left next ? (2^x-frac2^x2^2=3*2^13) exactly how do we get portion on the left side ? (2^x(1-frac12^2)=3*2^13) how after this (2^x(frac2^2-12^2)=3*2^13) we get this top top the left side (2^x*frac32^2=3*2^13) and also how we obtain this on the left next ? (2^x=2^15) hope this step will be clean after the vault one (x=15).many many thanks
Hi dave13Some formulae in exponents the you need to remember in exponents(a^0 = 1) | (a^1 = a) | (sqrta = a^frac12) | (a^-n = frac1a^n)(a^m+n = a^m*a^n) | (fraca^ma^n=a^m−n) | (a^n = frac1a^-n)Coming earlier to the difficulty at hand(2^x-2^x*2^-2=3*2^13) (2^x-frac2^x2^2=3*2^13) Here, (2^x-2 = 2^x + (-2) = 2^x*2^-2) (2^x(1-frac12^2)=3*2^13) Here, us take (2^x) as common from both the expressions(2^x(frac2^2-12^2)=3*2^13) Here, we leveling (1 - frac12^2) as (frac2^2 - 12^2 = frac4-12^2 = frac32^2)(2^x*frac32^2=3*2^13) -> (2^x=2^15) Here, we take (2^2) from left hand side to ideal hand side
pushpitkc, thanks for explanation, i somehow dont get based on which formula did you solve the below expression, (you administer all formulas yet i couldnt recognize the sample (i average which formula to apply) Here, (2^x-2 = 2^x + (-2) = 2^x*2^-2) can you please define somehow thanks and also have a great weekend generis maybe you can describe from various angle if such angle exist ? I chase quant like dog chases its story … trying come "catch" knowledge ..., having tough time taking care of exponents now hope space enjoying the weekend as well

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